3(b-7)+1=2(b+1)

Solution for 3(b-7)+1=2(b+1) equation:

Simplifying
3(b + -7) + 1 = 2(b + 1)

Reorder the terms:
3(-7 + b) + 1 = 2(b + 1)
(-7 * 3 + b * 3) + 1 = 2(b + 1)
(-21 + 3b) + 1 = 2(b + 1)

Reorder the terms:
-21 + 1 + 3b = 2(b + 1)

Combine like terms: -21 + 1 = -20
-20 + 3b = 2(b + 1)

Reorder the terms:
-20 + 3b = 2(1 + b)
-20 + 3b = (1 * 2 + b * 2)
-20 + 3b = (2 + 2b)

Solving
-20 + 3b = 2 + 2b

Solving for variable 'b'.

Move all terms containing b to the left, all other terms to the right.

Add '-2b' to each side of the equation.
-20 + 3b + -2b = 2 + 2b + -2b

Combine like terms: 3b + -2b = 1b
-20 + 1b = 2 + 2b + -2b

Combine like terms: 2b + -2b = 0
-20 + 1b = 2 + 0
-20 + 1b = 2

Add '20' to each side of the equation.
-20 + 20 + 1b = 2 + 20

Combine like terms: -20 + 20 = 0
0 + 1b = 2 + 20
1b = 2 + 20

Combine like terms: 2 + 20 = 22
1b = 22

Divide each side by '1'.
b = 22

Simplifying
b = 22