3(b-7)+4=28-2b

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Solution for 3(b-7)+4=28-2b equation: 



3(b-7)+4=28-2b

We move all terms to the left:

3(b-7)+4-(28-2b)=0

We add all the numbers together, and all the variables

3(b-7)-(-2b+28)+4=0

We multiply parentheses

3b-(-2b+28)-21+4=0

We get rid of parentheses

3b+2b-28-21+4=0

We add all the numbers together, and all the variables

5b-45=0

We move all terms containing b to the left, all other terms to the right

5b=45

b=45/5

b=9

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