3(b-7)-16=2(5b+1)-4

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Solution for 3(b-7)-16=2(5b+1)-4 equation: 



3(b-7)-16=2(5b+1)-4

We move all terms to the left:

3(b-7)-16-(2(5b+1)-4)=0

We multiply parentheses

3b-(2(5b+1)-4)-21-16=0



We calculate terms in parentheses: -(2(5b+1)-4), so:

2(5b+1)-4

We multiply parentheses

10b+2-4

We add all the numbers together, and all the variables

10b-2

Back to the equation:

-(10b-2)



We add all the numbers together, and all the variables

3b-(10b-2)-37=0

We get rid of parentheses

3b-10b+2-37=0

We add all the numbers together, and all the variables

-7b-35=0

We move all terms containing b to the left, all other terms to the right

-7b=35

b=35/-7

b=-5

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