3(b/5)=8b-20

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Solution for 3(b/5)=8b-20 equation: 



3(b/5)=8b-20

We move all terms to the left:

3(b/5)-(8b-20)=0

We add all the numbers together, and all the variables

3(+b/5)-(8b-20)=0

We multiply parentheses

3b-(8b-20)=0

We get rid of parentheses

3b-8b+20=0

We add all the numbers together, and all the variables

-5b+20=0

We move all terms containing b to the left, all other terms to the right

-5b=-20

b=-20/-5

b=+4

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