3(bx-cy)=d

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Solution for 3(bx-cy)=d equation: 


Simplifying
3(bx + -1cy) = d
(bx * 3 + -1cy * 3) = d
(3bx + -3cy) = d

Solving
3bx + -3cy = d

Solving for variable 'b'.

Move all terms containing b to the left, all other terms to the right.

Add '3cy' to each side of the equation.
3bx + -3cy + 3cy = 3cy + d

Combine like terms: -3cy + 3cy = 0
3bx + 0 = 3cy + d
3bx = 3cy + d

Divide each side by '3x'.
b = cx-1y + 0.3333333333dx-1

Simplifying
b = cx-1y + 0.3333333333dx-1

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