3(c+1)+2(c+5)=18

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Solution for 3(c+1)+2(c+5)=18 equation: 



3(c+1)+2(c+5)=18

We move all terms to the left:

3(c+1)+2(c+5)-(18)=0

We multiply parentheses

3c+2c+3+10-18=0

We add all the numbers together, and all the variables

5c-5=0

We move all terms containing c to the left, all other terms to the right

5c=5

c=5/5

c=1

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