3(c+1)-2=13

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Solution for 3(c+1)-2=13 equation:


Simplifying
3(c + 1) + -2 = 13

Reorder the terms:
3(1 + c) + -2 = 13
(1 * 3 + c * 3) + -2 = 13
(3 + 3c) + -2 = 13

Reorder the terms:
3 + -2 + 3c = 13

Combine like terms: 3 + -2 = 1
1 + 3c = 13

Solving
1 + 3c = 13

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-1' to each side of the equation.
1 + -1 + 3c = 13 + -1

Combine like terms: 1 + -1 = 0
0 + 3c = 13 + -1
3c = 13 + -1

Combine like terms: 13 + -1 = 12
3c = 12

Divide each side by '3'.
c = 4

Simplifying
c = 4

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