3(c+1)=2(c-5)

Solution for 3(c+1)=2(c-5) equation:

Simplifying
3(c + 1) = 2(c + -5)

Reorder the terms:
3(1 + c) = 2(c + -5)
(1 * 3 + c * 3) = 2(c + -5)
(3 + 3c) = 2(c + -5)

Reorder the terms:
3 + 3c = 2(-5 + c)
3 + 3c = (-5 * 2 + c * 2)
3 + 3c = (-10 + 2c)

Solving
3 + 3c = -10 + 2c

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-2c' to each side of the equation.
3 + 3c + -2c = -10 + 2c + -2c

Combine like terms: 3c + -2c = 1c
3 + 1c = -10 + 2c + -2c

Combine like terms: 2c + -2c = 0
3 + 1c = -10 + 0
3 + 1c = -10

Add '-3' to each side of the equation.
3 + -3 + 1c = -10 + -3

Combine like terms: 3 + -3 = 0
0 + 1c = -10 + -3
1c = -10 + -3

Combine like terms: -10 + -3 = -13
1c = -13

Divide each side by '1'.
c = -13

Simplifying
c = -13