3(c+1)=4-(c-3)

Solution for 3(c+1)=4-(c-3) equation:

Simplifying
3(c + 1) = 4 + -1(c + -3)

Reorder the terms:
3(1 + c) = 4 + -1(c + -3)
(1 * 3 + c * 3) = 4 + -1(c + -3)
(3 + 3c) = 4 + -1(c + -3)

Reorder the terms:
3 + 3c = 4 + -1(-3 + c)
3 + 3c = 4 + (-3 * -1 + c * -1)
3 + 3c = 4 + (3 + -1c)

Combine like terms: 4 + 3 = 7
3 + 3c = 7 + -1c

Solving
3 + 3c = 7 + -1c

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add 'c' to each side of the equation.
3 + 3c + c = 7 + -1c + c

Combine like terms: 3c + c = 4c
3 + 4c = 7 + -1c + c

Combine like terms: -1c + c = 0
3 + 4c = 7 + 0
3 + 4c = 7

Add '-3' to each side of the equation.
3 + -3 + 4c = 7 + -3

Combine like terms: 3 + -3 = 0
0 + 4c = 7 + -3
4c = 7 + -3

Combine like terms: 7 + -3 = 4
4c = 4

Divide each side by '4'.
c = 1

Simplifying
c = 1