3(c+2)+1=5c-1

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Solution for 3(c+2)+1=5c-1 equation:


Simplifying
3(c + 2) + 1 = 5c + -1

Reorder the terms:
3(2 + c) + 1 = 5c + -1
(2 * 3 + c * 3) + 1 = 5c + -1
(6 + 3c) + 1 = 5c + -1

Reorder the terms:
6 + 1 + 3c = 5c + -1

Combine like terms: 6 + 1 = 7
7 + 3c = 5c + -1

Reorder the terms:
7 + 3c = -1 + 5c

Solving
7 + 3c = -1 + 5c

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-5c' to each side of the equation.
7 + 3c + -5c = -1 + 5c + -5c

Combine like terms: 3c + -5c = -2c
7 + -2c = -1 + 5c + -5c

Combine like terms: 5c + -5c = 0
7 + -2c = -1 + 0
7 + -2c = -1

Add '-7' to each side of the equation.
7 + -7 + -2c = -1 + -7

Combine like terms: 7 + -7 = 0
0 + -2c = -1 + -7
-2c = -1 + -7

Combine like terms: -1 + -7 = -8
-2c = -8

Divide each side by '-2'.
c = 4

Simplifying
c = 4

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