3(c+2)+1c+1=57

Solution for 3(c+2)+1c+1=57 equation:

Simplifying
3(c + 2) + 1c + 1 = 57

Reorder the terms:
3(2 + c) + 1c + 1 = 57
(2 * 3 + c * 3) + 1c + 1 = 57
(6 + 3c) + 1c + 1 = 57

Reorder the terms:
6 + 1 + 3c + 1c = 57

Combine like terms: 6 + 1 = 7
7 + 3c + 1c = 57

Combine like terms: 3c + 1c = 4c
7 + 4c = 57

Solving
7 + 4c = 57

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-7' to each side of the equation.
7 + -7 + 4c = 57 + -7

Combine like terms: 7 + -7 = 0
0 + 4c = 57 + -7
4c = 57 + -7

Combine like terms: 57 + -7 = 50
4c = 50

Divide each side by '4'.
c = 12.5

Simplifying
c = 12.5