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3(c+2)+4=10+3c
We move all terms to the left:
3(c+2)+4-(10+3c)=0
We add all the numbers together, and all the variables
3(c+2)-(3c+10)+4=0
We multiply parentheses
3c-(3c+10)+6+4=0
We get rid of parentheses
3c-3c-10+6+4=0
We add all the numbers together, and all the variables
=0
c=0/1
c=0
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