3(c+2)+6=24

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Solution for 3(c+2)+6=24 equation: 



3(c+2)+6=24

We move all terms to the left:

3(c+2)+6-(24)=0

We add all the numbers together, and all the variables

3(c+2)-18=0

We multiply parentheses

3c+6-18=0

We add all the numbers together, and all the variables

3c-12=0

We move all terms containing c to the left, all other terms to the right

3c=12

c=12/3

c=4

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