3(c+2)+c+1=58

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Solution for 3(c+2)+c+1=58 equation: 



3(c+2)+c+1=58

We move all terms to the left:

3(c+2)+c+1-(58)=0

We add all the numbers together, and all the variables

c+3(c+2)-57=0

We multiply parentheses

c+3c+6-57=0

We add all the numbers together, and all the variables

4c-51=0

We move all terms containing c to the left, all other terms to the right

4c=51

c=51/4

c=12+3/4

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