3(c+2)-5=9

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Solution for 3(c+2)-5=9 equation: 



3(c+2)-5=9

We move all terms to the left:

3(c+2)-5-(9)=0

We add all the numbers together, and all the variables

3(c+2)-14=0

We multiply parentheses

3c+6-14=0

We add all the numbers together, and all the variables

3c-8=0

We move all terms containing c to the left, all other terms to the right

3c=8

c=8/3

c=2+2/3

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