3(c+2)=12c=

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Solution for 3(c+2)=12c= equation: 



3(c+2)=12c=

We move all terms to the left:

3(c+2)-(12c)=0

We add all the numbers together, and all the variables

-12c+3(c+2)=0

We multiply parentheses

-12c+3c+6=0

We add all the numbers together, and all the variables

-9c+6=0

We move all terms containing c to the left, all other terms to the right

-9c=-6

c=-6/-9

c=2/3

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