3(c+2)=2(2c+7)

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Solution for 3(c+2)=2(2c+7) equation: 



3(c+2)=2(2c+7)

We move all terms to the left:

3(c+2)-(2(2c+7))=0

We multiply parentheses

3c-(2(2c+7))+6=0



We calculate terms in parentheses: -(2(2c+7)), so:

2(2c+7)

We multiply parentheses

4c+14

Back to the equation:

-(4c+14)



We get rid of parentheses

3c-4c-14+6=0

We add all the numbers together, and all the variables

-1c-8=0

We move all terms containing c to the left, all other terms to the right

-c=8

c=8/-1

c=-8

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