3(c+2)=2c+12

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Solution for 3(c+2)=2c+12 equation: 



3(c+2)=2c+12

We move all terms to the left:

3(c+2)-(2c+12)=0

We multiply parentheses

3c-(2c+12)+6=0

We get rid of parentheses

3c-2c-12+6=0

We add all the numbers together, and all the variables

c-6=0

We move all terms containing c to the left, all other terms to the right

c=6

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