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3(c+2)=2c+12
We move all terms to the left:
3(c+2)-(2c+12)=0
We multiply parentheses
3c-(2c+12)+6=0
We get rid of parentheses
3c-2c-12+6=0
We add all the numbers together, and all the variables
c-6=0
We move all terms containing c to the left, all other terms to the right
c=6
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