3(c+2)=34

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Solution for 3(c+2)=34 equation: 



3(c+2)=34

We move all terms to the left:

3(c+2)-(34)=0

We multiply parentheses

3c+6-34=0

We add all the numbers together, and all the variables

3c-28=0

We move all terms containing c to the left, all other terms to the right

3c=28

c=28/3

c=9+1/3

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