3(c+2)=5(c+1)=-7

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Solution for 3(c+2)=5(c+1)=-7 equation:



3(c+2)=5(c+1)=-7
We move all terms to the left:
3(c+2)-(5(c+1))=0
We multiply parentheses
3c-(5(c+1))+6=0
We calculate terms in parentheses: -(5(c+1)), so:
5(c+1)
We multiply parentheses
5c+5
Back to the equation:
-(5c+5)
We get rid of parentheses
3c-5c-5+6=0
We add all the numbers together, and all the variables
-2c+1=0
We move all terms containing c to the left, all other terms to the right
-2c=-1
c=-1/-2
c=1/2

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