3(c+2)=5(c+1)=-7

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Solution for 3(c+2)=5(c+1)=-7 equation: 



3(c+2)=5(c+1)=-7

We move all terms to the left:

3(c+2)-(5(c+1))=0

We multiply parentheses

3c-(5(c+1))+6=0



We calculate terms in parentheses: -(5(c+1)), so:

5(c+1)

We multiply parentheses

5c+5

Back to the equation:

-(5c+5)



We get rid of parentheses

3c-5c-5+6=0

We add all the numbers together, and all the variables

-2c+1=0

We move all terms containing c to the left, all other terms to the right

-2c=-1

c=-1/-2

c=1/2

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