3(c+2+1)=9c+3

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Solution for 3(c+2+1)=9c+3 equation:


Simplifying
3(c + 2 + 1) = 9c + 3

Reorder the terms:
3(2 + 1 + c) = 9c + 3

Combine like terms: 2 + 1 = 3
3(3 + c) = 9c + 3
(3 * 3 + c * 3) = 9c + 3
(9 + 3c) = 9c + 3

Reorder the terms:
9 + 3c = 3 + 9c

Solving
9 + 3c = 3 + 9c

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-9c' to each side of the equation.
9 + 3c + -9c = 3 + 9c + -9c

Combine like terms: 3c + -9c = -6c
9 + -6c = 3 + 9c + -9c

Combine like terms: 9c + -9c = 0
9 + -6c = 3 + 0
9 + -6c = 3

Add '-9' to each side of the equation.
9 + -9 + -6c = 3 + -9

Combine like terms: 9 + -9 = 0
0 + -6c = 3 + -9
-6c = 3 + -9

Combine like terms: 3 + -9 = -6
-6c = -6

Divide each side by '-6'.
c = 1

Simplifying
c = 1

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