3(c+3)+6c=3(c+4)-3

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Solution for 3(c+3)+6c=3(c+4)-3 equation:


Simplifying
3(c + 3) + 6c = 3(c + 4) + -3

Reorder the terms:
3(3 + c) + 6c = 3(c + 4) + -3
(3 * 3 + c * 3) + 6c = 3(c + 4) + -3
(9 + 3c) + 6c = 3(c + 4) + -3

Combine like terms: 3c + 6c = 9c
9 + 9c = 3(c + 4) + -3

Reorder the terms:
9 + 9c = 3(4 + c) + -3
9 + 9c = (4 * 3 + c * 3) + -3
9 + 9c = (12 + 3c) + -3

Reorder the terms:
9 + 9c = 12 + -3 + 3c

Combine like terms: 12 + -3 = 9
9 + 9c = 9 + 3c

Add '-9' to each side of the equation.
9 + -9 + 9c = 9 + -9 + 3c

Combine like terms: 9 + -9 = 0
0 + 9c = 9 + -9 + 3c
9c = 9 + -9 + 3c

Combine like terms: 9 + -9 = 0
9c = 0 + 3c
9c = 3c

Solving
9c = 3c

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-3c' to each side of the equation.
9c + -3c = 3c + -3c

Combine like terms: 9c + -3c = 6c
6c = 3c + -3c

Combine like terms: 3c + -3c = 0
6c = 0

Divide each side by '6'.
c = 0

Simplifying
c = 0

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