3(c+3)-6c-3(1-3c)=6

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Solution for 3(c+3)-6c-3(1-3c)=6 equation: 



3(c+3)-6c-3(1-3c)=6

We move all terms to the left:

3(c+3)-6c-3(1-3c)-(6)=0

We add all the numbers together, and all the variables

3(c+3)-6c-3(-3c+1)-6=0

We add all the numbers together, and all the variables

-6c+3(c+3)-3(-3c+1)-6=0

We multiply parentheses

-6c+3c+9c+9-3-6=0

We add all the numbers together, and all the variables

6c=0

c=0/6

c=0

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