3(c+3)=-2(c+5)

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Solution for 3(c+3)=-2(c+5) equation: 



3(c+3)=-2(c+5)

We move all terms to the left:

3(c+3)-(-2(c+5))=0

We multiply parentheses

3c-(-2(c+5))+9=0



We calculate terms in parentheses: -(-2(c+5)), so:

-2(c+5)

We multiply parentheses

-2c-10

Back to the equation:

-(-2c-10)



We get rid of parentheses

3c+2c+10+9=0

We add all the numbers together, and all the variables

5c+19=0

We move all terms containing c to the left, all other terms to the right

5c=-19

c=-19/5

c=-3+4/5

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