3(c+4)+c=2(c-5)

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Solution for 3(c+4)+c=2(c-5) equation:


Simplifying
3(c + 4) + c = 2(c + -5)

Reorder the terms:
3(4 + c) + c = 2(c + -5)
(4 * 3 + c * 3) + c = 2(c + -5)
(12 + 3c) + c = 2(c + -5)

Combine like terms: 3c + c = 4c
12 + 4c = 2(c + -5)

Reorder the terms:
12 + 4c = 2(-5 + c)
12 + 4c = (-5 * 2 + c * 2)
12 + 4c = (-10 + 2c)

Solving
12 + 4c = -10 + 2c

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-2c' to each side of the equation.
12 + 4c + -2c = -10 + 2c + -2c

Combine like terms: 4c + -2c = 2c
12 + 2c = -10 + 2c + -2c

Combine like terms: 2c + -2c = 0
12 + 2c = -10 + 0
12 + 2c = -10

Add '-12' to each side of the equation.
12 + -12 + 2c = -10 + -12

Combine like terms: 12 + -12 = 0
0 + 2c = -10 + -12
2c = -10 + -12

Combine like terms: -10 + -12 = -22
2c = -22

Divide each side by '2'.
c = -11

Simplifying
c = -11

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