3(c+4)-2c=16-4(c+5)

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Solution for 3(c+4)-2c=16-4(c+5) equation:


Simplifying
3(c + 4) + -2c = 16 + -4(c + 5)

Reorder the terms:
3(4 + c) + -2c = 16 + -4(c + 5)
(4 * 3 + c * 3) + -2c = 16 + -4(c + 5)
(12 + 3c) + -2c = 16 + -4(c + 5)

Combine like terms: 3c + -2c = 1c
12 + 1c = 16 + -4(c + 5)

Reorder the terms:
12 + 1c = 16 + -4(5 + c)
12 + 1c = 16 + (5 * -4 + c * -4)
12 + 1c = 16 + (-20 + -4c)

Combine like terms: 16 + -20 = -4
12 + 1c = -4 + -4c

Solving
12 + 1c = -4 + -4c

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '4c' to each side of the equation.
12 + 1c + 4c = -4 + -4c + 4c

Combine like terms: 1c + 4c = 5c
12 + 5c = -4 + -4c + 4c

Combine like terms: -4c + 4c = 0
12 + 5c = -4 + 0
12 + 5c = -4

Add '-12' to each side of the equation.
12 + -12 + 5c = -4 + -12

Combine like terms: 12 + -12 = 0
0 + 5c = -4 + -12
5c = -4 + -12

Combine like terms: -4 + -12 = -16
5c = -16

Divide each side by '5'.
c = -3.2

Simplifying
c = -3.2

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