3(c+4)-6c=2(4-2c)

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Solution for 3(c+4)-6c=2(4-2c) equation:



3(c+4)-6c=2(4-2c)
We move all terms to the left:
3(c+4)-6c-(2(4-2c))=0
We add all the numbers together, and all the variables
3(c+4)-6c-(2(-2c+4))=0
We add all the numbers together, and all the variables
-6c+3(c+4)-(2(-2c+4))=0
We multiply parentheses
-6c+3c-(2(-2c+4))+12=0
We calculate terms in parentheses: -(2(-2c+4)), so:
2(-2c+4)
We multiply parentheses
-4c+8
Back to the equation:
-(-4c+8)
We add all the numbers together, and all the variables
-3c-(-4c+8)+12=0
We get rid of parentheses
-3c+4c-8+12=0
We add all the numbers together, and all the variables
c+4=0
We move all terms containing c to the left, all other terms to the right
c=-4

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