3(c+4)-c=-7(c-2)

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Solution for 3(c+4)-c=-7(c-2) equation: 



3(c+4)-c=-7(c-2)

We move all terms to the left:

3(c+4)-c-(-7(c-2))=0

We add all the numbers together, and all the variables

-1c+3(c+4)-(-7(c-2))=0

We multiply parentheses

-1c+3c-(-7(c-2))+12=0



We calculate terms in parentheses: -(-7(c-2)), so:

-7(c-2)

We multiply parentheses

-7c+14

Back to the equation:

-(-7c+14)



We add all the numbers together, and all the variables

2c-(-7c+14)+12=0

We get rid of parentheses

2c+7c-14+12=0

We add all the numbers together, and all the variables

9c-2=0

We move all terms containing c to the left, all other terms to the right

9c=2

c=2/9

c=2/9

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