3(c+4)=2(c+4)+c

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Solution for 3(c+4)=2(c+4)+c equation: 


Simplifying
3(c + 4) = 2(c + 4) + c

Reorder the terms:
3(4 + c) = 2(c + 4) + c
(4 * 3 + c * 3) = 2(c + 4) + c
(12 + 3c) = 2(c + 4) + c

Reorder the terms:
12 + 3c = 2(4 + c) + c
12 + 3c = (4 * 2 + c * 2) + c
12 + 3c = (8 + 2c) + c

Combine like terms: 2c + c = 3c
12 + 3c = 8 + 3c

Add '-3c' to each side of the equation.
12 + 3c + -3c = 8 + 3c + -3c

Combine like terms: 3c + -3c = 0
12 + 0 = 8 + 3c + -3c
12 = 8 + 3c + -3c

Combine like terms: 3c + -3c = 0
12 = 8 + 0
12 = 8

Solving
12 = 8

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.

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