3(c+4)=2(c+6)

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Solution for 3(c+4)=2(c+6) equation: 



3(c+4)=2(c+6)

We move all terms to the left:

3(c+4)-(2(c+6))=0

We multiply parentheses

3c-(2(c+6))+12=0



We calculate terms in parentheses: -(2(c+6)), so:

2(c+6)

We multiply parentheses

2c+12

Back to the equation:

-(2c+12)



We get rid of parentheses

3c-2c-12+12=0

We add all the numbers together, and all the variables

c=0

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