3(c+4)=4c-6

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Solution for 3(c+4)=4c-6 equation: 



3(c+4)=4c-6

We move all terms to the left:

3(c+4)-(4c-6)=0

We multiply parentheses

3c-(4c-6)+12=0

We get rid of parentheses

3c-4c+6+12=0

We add all the numbers together, and all the variables

-1c+18=0

We move all terms containing c to the left, all other terms to the right

-c=-18

c=-18/-1

c=+18

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