3(c+5)+2(2c-3)-c-9=0

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Solution for 3(c+5)+2(2c-3)-c-9=0 equation:


Simplifying
3(c + 5) + 2(2c + -3) + -1c + -9 = 0

Reorder the terms:
3(5 + c) + 2(2c + -3) + -1c + -9 = 0
(5 * 3 + c * 3) + 2(2c + -3) + -1c + -9 = 0
(15 + 3c) + 2(2c + -3) + -1c + -9 = 0

Reorder the terms:
15 + 3c + 2(-3 + 2c) + -1c + -9 = 0
15 + 3c + (-3 * 2 + 2c * 2) + -1c + -9 = 0
15 + 3c + (-6 + 4c) + -1c + -9 = 0

Reorder the terms:
15 + -6 + -9 + 3c + 4c + -1c = 0

Combine like terms: 15 + -6 = 9
9 + -9 + 3c + 4c + -1c = 0

Combine like terms: 9 + -9 = 0
0 + 3c + 4c + -1c = 0
3c + 4c + -1c = 0

Combine like terms: 3c + 4c = 7c
7c + -1c = 0

Combine like terms: 7c + -1c = 6c
6c = 0

Solving
6c = 0

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Divide each side by '6'.
c = 0

Simplifying
c = 0

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