3(c+5)-2=2(c+6)+2

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Solution for 3(c+5)-2=2(c+6)+2 equation:


Simplifying
3(c + 5) + -2 = 2(c + 6) + 2

Reorder the terms:
3(5 + c) + -2 = 2(c + 6) + 2
(5 * 3 + c * 3) + -2 = 2(c + 6) + 2
(15 + 3c) + -2 = 2(c + 6) + 2

Reorder the terms:
15 + -2 + 3c = 2(c + 6) + 2

Combine like terms: 15 + -2 = 13
13 + 3c = 2(c + 6) + 2

Reorder the terms:
13 + 3c = 2(6 + c) + 2
13 + 3c = (6 * 2 + c * 2) + 2
13 + 3c = (12 + 2c) + 2

Reorder the terms:
13 + 3c = 12 + 2 + 2c

Combine like terms: 12 + 2 = 14
13 + 3c = 14 + 2c

Solving
13 + 3c = 14 + 2c

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-2c' to each side of the equation.
13 + 3c + -2c = 14 + 2c + -2c

Combine like terms: 3c + -2c = 1c
13 + 1c = 14 + 2c + -2c

Combine like terms: 2c + -2c = 0
13 + 1c = 14 + 0
13 + 1c = 14

Add '-13' to each side of the equation.
13 + -13 + 1c = 14 + -13

Combine like terms: 13 + -13 = 0
0 + 1c = 14 + -13
1c = 14 + -13

Combine like terms: 14 + -13 = 1
1c = 1

Divide each side by '1'.
c = 1

Simplifying
c = 1

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