3(c+5)=12+4c

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Solution for 3(c+5)=12+4c equation: 



3(c+5)=12+4c

We move all terms to the left:

3(c+5)-(12+4c)=0

We add all the numbers together, and all the variables

3(c+5)-(4c+12)=0

We multiply parentheses

3c-(4c+12)+15=0

We get rid of parentheses

3c-4c-12+15=0

We add all the numbers together, and all the variables

-1c+3=0

We move all terms containing c to the left, all other terms to the right

-c=-3

c=-3/-1

c=+3

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