3(c+5)=2(c+3)-11

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Solution for 3(c+5)=2(c+3)-11 equation:


Simplifying
3(c + 5) = 2(c + 3) + -11

Reorder the terms:
3(5 + c) = 2(c + 3) + -11
(5 * 3 + c * 3) = 2(c + 3) + -11
(15 + 3c) = 2(c + 3) + -11

Reorder the terms:
15 + 3c = 2(3 + c) + -11
15 + 3c = (3 * 2 + c * 2) + -11
15 + 3c = (6 + 2c) + -11

Reorder the terms:
15 + 3c = 6 + -11 + 2c

Combine like terms: 6 + -11 = -5
15 + 3c = -5 + 2c

Solving
15 + 3c = -5 + 2c

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-2c' to each side of the equation.
15 + 3c + -2c = -5 + 2c + -2c

Combine like terms: 3c + -2c = 1c
15 + 1c = -5 + 2c + -2c

Combine like terms: 2c + -2c = 0
15 + 1c = -5 + 0
15 + 1c = -5

Add '-15' to each side of the equation.
15 + -15 + 1c = -5 + -15

Combine like terms: 15 + -15 = 0
0 + 1c = -5 + -15
1c = -5 + -15

Combine like terms: -5 + -15 = -20
1c = -20

Divide each side by '1'.
c = -20

Simplifying
c = -20

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