3(c+5)=30+5c

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Solution for 3(c+5)=30+5c equation:



3(c+5)=30+5c
We move all terms to the left:
3(c+5)-(30+5c)=0
We add all the numbers together, and all the variables
3(c+5)-(5c+30)=0
We multiply parentheses
3c-(5c+30)+15=0
We get rid of parentheses
3c-5c-30+15=0
We add all the numbers together, and all the variables
-2c-15=0
We move all terms containing c to the left, all other terms to the right
-2c=15
c=15/-2
c=-7+1/2

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