3(c+6)=2-(c-4)

Solution for 3(c+6)=2-(c-4) equation:

3(c+6)=2-(c-4)

We move all terms to the left:

3(c+6)-(2-(c-4))=0

We multiply parentheses

3c-(2-(c-4))+18=0


We calculate terms in parentheses: -(2-(c-4)), so:

2-(c-4)

determiningTheFunctionDomain
-(c-4)+2

We get rid of parentheses

-c+4+2

We add all the numbers together, and all the variables

-1c+6

Back to the equation:

-(-1c+6)


We get rid of parentheses

3c+1c-6+18=0

We add all the numbers together, and all the variables

4c+12=0

We move all terms containing c to the left, all other terms to the right

4c=-12

c=-12/4

c=-3