3(c-1)+(3c+1)=-(3c+1)

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Solution for 3(c-1)+(3c+1)=-(3c+1) equation: 



3(c-1)+(3c+1)=-(3c+1)

We move all terms to the left:

3(c-1)+(3c+1)-(-(3c+1))=0

We multiply parentheses

3c+(3c+1)-(-(3c+1))-3=0

We get rid of parentheses

3c+3c-(-(3c+1))+1-3=0



We calculate terms in parentheses: -(-(3c+1)), so:

-(3c+1)

We get rid of parentheses

-3c-1

Back to the equation:

-(-3c-1)



We add all the numbers together, and all the variables

6c-(-3c-1)-2=0

We get rid of parentheses

6c+3c+1-2=0

We add all the numbers together, and all the variables

9c-1=0

We move all terms containing c to the left, all other terms to the right

9c=1

c=1/9

c=1/9

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