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3(c-1)+2(3c+1)=(3c+1)=(3c+1)
We move all terms to the left:
3(c-1)+2(3c+1)-((3c+1))=0
We multiply parentheses
3c+6c-((3c+1))-3+2=0
We calculate terms in parentheses: -((3c+1)), so:We add all the numbers together, and all the variables
(3c+1)
We get rid of parentheses
3c+1
Back to the equation:
-(3c+1)
9c-(3c+1)-1=0
We get rid of parentheses
9c-3c-1-1=0
We add all the numbers together, and all the variables
6c-2=0
We move all terms containing c to the left, all other terms to the right
6c=2
c=2/6
c=1/3
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