3(c-1)=18-5(c+1)

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Solution for 3(c-1)=18-5(c+1) equation: 



3(c-1)=18-5(c+1)

We move all terms to the left:

3(c-1)-(18-5(c+1))=0

We multiply parentheses

3c-(18-5(c+1))-3=0



We calculate terms in parentheses: -(18-5(c+1)), so:

18-5(c+1)

determiningTheFunctionDomain
-5(c+1)+18

We multiply parentheses

-5c-5+18

We add all the numbers together, and all the variables

-5c+13

Back to the equation:

-(-5c+13)



We get rid of parentheses

3c+5c-13-3=0

We add all the numbers together, and all the variables

8c-16=0

We move all terms containing c to the left, all other terms to the right

8c=16

c=16/8

c=2

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