3(c-10)+-3=15

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Solution for 3(c-10)+-3=15 equation: 



3(c-10)+-3=15

We move all terms to the left:

3(c-10)+-3-(15)=0

determiningTheFunctionDomain
3(c-10)-3-15+=0

We add all the numbers together, and all the variables

3(c-10)=0

We multiply parentheses

3c-30=0

We move all terms containing c to the left, all other terms to the right

3c=30

c=30/3

c=10

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