3(c-11)=2(8+c)

Solution for 3(c-11)=2(8+c) equation:

3(c-11)=2(8+c)

We move all terms to the left:

3(c-11)-(2(8+c))=0

We add all the numbers together, and all the variables

3(c-11)-(2(c+8))=0

We multiply parentheses

3c-(2(c+8))-33=0


We calculate terms in parentheses: -(2(c+8)), so:

2(c+8)

We multiply parentheses

2c+16

Back to the equation:

-(2c+16)


We get rid of parentheses

3c-2c-16-33=0

We add all the numbers together, and all the variables

c-49=0

We move all terms containing c to the left, all other terms to the right

c=49