3(c-12)+-7=11

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Solution for 3(c-12)+-7=11 equation: 



3(c-12)+-7=11

We move all terms to the left:

3(c-12)+-7-(11)=0

determiningTheFunctionDomain
3(c-12)-7-11+=0

We add all the numbers together, and all the variables

3(c-12)=0

We multiply parentheses

3c-36=0

We move all terms containing c to the left, all other terms to the right

3c=36

c=36/3

c=12

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