3(c-14)+7(c-12)=14

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Solution for 3(c-14)+7(c-12)=14 equation: 



3(c-14)+7(c-12)=14

We move all terms to the left:

3(c-14)+7(c-12)-(14)=0

We multiply parentheses

3c+7c-42-84-14=0

We add all the numbers together, and all the variables

10c-140=0

We move all terms containing c to the left, all other terms to the right

10c=140

c=140/10

c=14

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