3(c-15)=4(c+2)

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Solution for 3(c-15)=4(c+2) equation: 



3(c-15)=4(c+2)

We move all terms to the left:

3(c-15)-(4(c+2))=0

We multiply parentheses

3c-(4(c+2))-45=0



We calculate terms in parentheses: -(4(c+2)), so:

4(c+2)

We multiply parentheses

4c+8

Back to the equation:

-(4c+8)



We get rid of parentheses

3c-4c-8-45=0

We add all the numbers together, and all the variables

-1c-53=0

We move all terms containing c to the left, all other terms to the right

-c=53

c=53/-1

c=-53

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