3(c-19)=2(c-23)

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Solution for 3(c-19)=2(c-23) equation: 



3(c-19)=2(c-23)

We move all terms to the left:

3(c-19)-(2(c-23))=0

We multiply parentheses

3c-(2(c-23))-57=0



We calculate terms in parentheses: -(2(c-23)), so:

2(c-23)

We multiply parentheses

2c-46

Back to the equation:

-(2c-46)



We get rid of parentheses

3c-2c+46-57=0

We add all the numbers together, and all the variables

c-11=0

We move all terms containing c to the left, all other terms to the right

c=11

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