3(c-19)=2(c-23)

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Solution for 3(c-19)=2(c-23) equation:



3(c-19)=2(c-23)
We move all terms to the left:
3(c-19)-(2(c-23))=0
We multiply parentheses
3c-(2(c-23))-57=0
We calculate terms in parentheses: -(2(c-23)), so:
2(c-23)
We multiply parentheses
2c-46
Back to the equation:
-(2c-46)
We get rid of parentheses
3c-2c+46-57=0
We add all the numbers together, and all the variables
c-11=0
We move all terms containing c to the left, all other terms to the right
c=11

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