3(c-2)+5=2(c+1)

Solution for 3(c-2)+5=2(c+1) equation:

Simplifying
3(c + -2) + 5 = 2(c + 1)

Reorder the terms:
3(-2 + c) + 5 = 2(c + 1)
(-2 * 3 + c * 3) + 5 = 2(c + 1)
(-6 + 3c) + 5 = 2(c + 1)

Reorder the terms:
-6 + 5 + 3c = 2(c + 1)

Combine like terms: -6 + 5 = -1
-1 + 3c = 2(c + 1)

Reorder the terms:
-1 + 3c = 2(1 + c)
-1 + 3c = (1 * 2 + c * 2)
-1 + 3c = (2 + 2c)

Solving
-1 + 3c = 2 + 2c

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-2c' to each side of the equation.
-1 + 3c + -2c = 2 + 2c + -2c

Combine like terms: 3c + -2c = 1c
-1 + 1c = 2 + 2c + -2c

Combine like terms: 2c + -2c = 0
-1 + 1c = 2 + 0
-1 + 1c = 2

Add '1' to each side of the equation.
-1 + 1 + 1c = 2 + 1

Combine like terms: -1 + 1 = 0
0 + 1c = 2 + 1
1c = 2 + 1

Combine like terms: 2 + 1 = 3
1c = 3

Divide each side by '1'.
c = 3

Simplifying
c = 3