3(c-2)+6=5(c+4)

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Solution for 3(c-2)+6=5(c+4) equation: 



3(c-2)+6=5(c+4)

We move all terms to the left:

3(c-2)+6-(5(c+4))=0

We multiply parentheses

3c-(5(c+4))-6+6=0



We calculate terms in parentheses: -(5(c+4)), so:

5(c+4)

We multiply parentheses

5c+20

Back to the equation:

-(5c+20)



We add all the numbers together, and all the variables

3c-(5c+20)=0

We get rid of parentheses

3c-5c-20=0

We add all the numbers together, and all the variables

-2c-20=0

We move all terms containing c to the left, all other terms to the right

-2c=20

c=20/-2

c=-10

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