3(c-2)=-5(c-1)+5

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Solution for 3(c-2)=-5(c-1)+5 equation: 



3(c-2)=-5(c-1)+5

We move all terms to the left:

3(c-2)-(-5(c-1)+5)=0

We multiply parentheses

3c-(-5(c-1)+5)-6=0



We calculate terms in parentheses: -(-5(c-1)+5), so:

-5(c-1)+5

We multiply parentheses

-5c+5+5

We add all the numbers together, and all the variables

-5c+10

Back to the equation:

-(-5c+10)



We get rid of parentheses

3c+5c-10-6=0

We add all the numbers together, and all the variables

8c-16=0

We move all terms containing c to the left, all other terms to the right

8c=16

c=16/8

c=2

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