3(c-2)=2(c-3)

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Solution for 3(c-2)=2(c-3) equation: 



3(c-2)=2(c-3)

We move all terms to the left:

3(c-2)-(2(c-3))=0

We multiply parentheses

3c-(2(c-3))-6=0



We calculate terms in parentheses: -(2(c-3)), so:

2(c-3)

We multiply parentheses

2c-6

Back to the equation:

-(2c-6)



We get rid of parentheses

3c-2c+6-6=0

We add all the numbers together, and all the variables

c=0

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